the inner and outer circumferences of track are 176m and 264m .find the width of track . answer in detail
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vinayak19:
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The inner and outer circumferences of track are 176m and 264m
so radius of inner circle=?
circumference is 176
176=2*22/7*radius
176=44/7 *radius
radius=176*7/44
radius=28cm
radius of inner circle=?
circumference is 176
176=2*22/7*radius area of iner circle=22/7 *radius*radius
176=44/7 *radius =2464m²
radius=176*7/44
radius=28cm
radius of outer circle=?
circumference is 264 area of outer circle=22/7*radius²
264=*22/7*radius =5544m²
264 =44/7 *radius
radius=264*7/44
radius=42cm
area of path=area of outercirlce-inner circle
=5544-2464
=3080m²
so radius of inner circle=?
circumference is 176
176=2*22/7*radius
176=44/7 *radius
radius=176*7/44
radius=28cm
radius of inner circle=?
circumference is 176
176=2*22/7*radius area of iner circle=22/7 *radius*radius
176=44/7 *radius =2464m²
radius=176*7/44
radius=28cm
radius of outer circle=?
circumference is 264 area of outer circle=22/7*radius²
264=*22/7*radius =5544m²
264 =44/7 *radius
radius=264*7/44
radius=42cm
area of path=area of outercirlce-inner circle
=5544-2464
=3080m²
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