Question

The inner and outer radii of a cylindrical pipe are 5cm and 5.5 cm, respectively. Find the area of the cross-section of the pipe.​

Answer 1

Answer:

16.485 cm²

Solution:

⇒ Given:

Inner radius of the cylindrical pipe = 5 cm

Outer radius of the cylindrical pipe = 5.5 cm

In this question, we have to find the area of the cross section of the cylindrical pipe.

Let the inner radius be r and the outer radius be R.

Formula to be used :

$\sf{\pi\:R^2-\pi\:r^2}$

→ Taking out the common terms:

$\sf{\pi(R^2-r^2)}$

Hence the required area is :

$\sf{\boxed{\pi(R^2-r^2)}}$

Now,

r = 5 cm

R = 5.5 cm

Substituting the values in the equation:

$\sf{=\pi(5.5^2-5^2)}}$

Giving the value of π as 3.14:

$\sf{=3.14(30.25-25}$

$\sf{=3.14\times5.25}$

$\sf{=16.485\:cm^2}$

Hence the area of the cross-section of the cylindrical pipe is 16.485 cm².

Knowledge Bytes:

→ What is cross section?

If you have noticed a cylindrical pipe, you must have seen that it is not completely closed and that there is a small ring like structure formed by the material from which the pipe is made. The inner part will have a radius r and the outer part will have a radius R. This is a cross section. In order to find the area of a cross section, we have to multiply both the inner and outer radius separately with pi and then subtract those values.

Answer 2

• Answer:
• Answer:16.485 cm²
• Answer:16.485 cm²Solution:
• Answer:16.485 cm²Solution:⇒ Given:
• Answer:16.485 cm²Solution:⇒ Given:Inner radius of the cylindrical pipe = 5 cm
• Answer:16.485 cm²Solution:⇒ Given:Inner radius of the cylindrical pipe = 5 cmOuter radius of the cylindrical pipe = 5.5 cm
• Answer:16.485 cm²Solution:⇒ Given:Inner radius of the cylindrical pipe = 5 cmOuter radius of the cylindrical pipe = 5.5 cmIn this question, we have to find the area of the cross section of the cylindrical pipe.
• Answer:16.485 cm²Solution:⇒ Given:Inner radius of the cylindrical pipe = 5 cmOuter radius of the cylindrical pipe = 5.5 cmIn this question, we have to find the area of the cross section of the cylindrical pipe.Let the inner radius be r and the outer radius be R.
• Answer:16.485 cm²Solution:⇒ Given:Inner radius of the cylindrical pipe = 5 cmOuter radius of the cylindrical pipe = 5.5 cmIn this question, we have to find the area of the cross section of the cylindrical pipe.Let the inner radius be r and the outer radius be R.Formula to be used :
• Answer:16.485 cm²Solution:⇒ Given:Inner radius of the cylindrical pipe = 5 cmOuter radius of the cylindrical pipe = 5.5 cmIn this question, we have to find the area of the cross section of the cylindrical pipe.Let the inner radius be r and the outer radius be R.Formula to be used :\sf{\pi\:R²-\pi\:r^2}πR2−πr2
• -\pi\:r^2}πR2−πr2→ Taking out the common terms:
• -\pi\:r^2}πR2−πr2→ Taking out the common terms:\sf{\pi(R²-r²)}π(R2−r2)
• )}π(R2−r2)Hence the required area is :
• )}π(R2−r2)Hence the required area is :\sf{\boxed{\pi(R²-r²)}}π(R2−r2)
• )}}π(R2−r2)Now,
• )}}π(R2−r2)Now,r = 5 cm
• )}}π(R2−r2)Now,r = 5 cmR = 5.5 cm
• )}}π(R2−r2)Now,r = 5 cmR = 5.5 cmSubstituting the values in the equation:
• )}}π(R2−r2)Now,r = 5 cmR = 5.5 cmSubstituting the values in the equation:\sf{=\pi(5.5²-5²)}}
• )}}Giving the value of π as 3.14:
• )}}Giving the value of π as 3.14:\sf{=3.14(30.25-25}=3.14(30.25−25
• )}}Giving the value of π as 3.14:\sf{=3.14(30.25-25}=3.14(30.25−25\sf{=3.14\times5.25}=3.14×5.25
• )}}Giving the value of π as 3.14:\sf{=3.14(30.25-25}=3.14(30.25−25\sf{=3.14\times5.25}=3.14×5.25\sf{=16.485\:cm^2}=16.485cm2
• )}}Giving the value of π as 3.14:\sf{=3.14(30.25-25}=3.14(30.25−25\sf{=3.14\times5.25}=3.14×5.25\sf{=16.485\:cm^2}=16.485cm2Hence the area of the cross-section of the cylindrical pipe is 16.48