the inner and outer radii of cylindrical pipe are 4cm and 5cm respectively. find the area of cross section of pipe .
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subtract area by taking inner radius from area by taking outer radius.....
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R = 5 cm,
r = 4 cm,
Area of cross section = π(R^2-r^2)
=28.285 sq. cm.
r = 4 cm,
Area of cross section = π(R^2-r^2)
=28.285 sq. cm.
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