Question

The inner circumference of a circular track is 121 m. The track is 3.5 m wide. Find the area of the
track.​

Answer 1

Answer:

461.6 m sq.

Step-by-step explanation:

Since the inner circumfrence is 121m,

2πr = 121

r = 121 x 7/44

therefore r = 19.25m

radius of outer track = 19.25 + 3.5

= 22.75m

area of inner circle = π x r x r

= 1163.5 m sq.

area of outer circle = π x r x r

= 1625.1 m sq.

area of track = 1625.1 - 1163.5

= 461.6 m sq.

Answer 2

HELLOW FRIEND,

INNER CIRCUMFERENCE = 121 m

2πr = 121 m

$= > 2 \times \frac{22}{7} \times r = 121 \: m \\ = > r \: = \: \frac{121}{2} \times \frac{7}{22} \\ = > r \: = 19.25$

OUTER CIRCLE'S RADIUS = 19.25+3.5

= 22.75 m

TOTLE AREA =

$= > \pi {r}^{2} \\ = > \frac{22}{7} \times {22.75}^{2} \\ = > 1626.625 \: {m}^{2}$

INNER CIRCLE'S AREA =

$= > \pi {r}^{2} \\ = > \frac{22}{7} \times {19.25}^{2} \\ = > 1164.625 \: {m}^{2}$

AREA OF TRACK = AREA OF TOTAL CIRCLE - AREA OF INNER CIRCLE.

AREA OF TRACK = 1626.625-1164.625

= 462 m^2.

THEREFORE,. THE AREA OF CIRCULAR TRACK IS 462m^2.