Math, asked by Subrat2418, 1 month ago

The inner circumference of a circular track is 176 m. The track is 7 m wide. Calculate the:
(a) area of the track.
(b) cost of putting up a fence along the outer circle at the rate of 12 rupees per metre.

Answers

Answered by anshikapatel27
2

Area of the track is 1386m^21386m

2

and Cost of putting up a fence along the outer circle at the rate of rs 12 per metre is Rs.2640

Step-by-step explanation:

Step-by-step explanation:

Circumference of circle = 2 \pi r2π r

Inner circumference = 176 m

So, 2 \times \frac{22}{7} \times r = 1762×

7

22

×r=176

r = 176 \times \frac{7}{22 \times 2}r=176×

22×2

7

r = 28r=28

Inner radius r = 28 m

The track is 7 m wide .

Outer radius R = 28+7 = 35 m

Area of track = Outer area - Inner area = \pi R^2-\pi r^2=\frac{22}{7}(35^2-28^2)=1386m^2πR

2

−πr

2

=

7

22

(35

2

−28

2

)=1386m

2

Outer circumference = 2 \pi R = 2 \times \frac{22}{7} \times 35=220 m2π R=2×

7

22

×35=220m

Cost of fencing 1 m = Rs.12

Cost of fencing 220 m = 12 \times 220 = Rs.264012×220=Rs.2640

Hence Area of the track is 1386m^21386m

2

and Cost of putting up a fence along the outer circle at the rate of rs 12 per metre is Rs.2640

Answered by deepnehra05
6

Step-by-step explanation:

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