Math, asked by aadiya4455, 4 days ago

the inner circumference of a circular track is 176 metre the track is 7 metre wide calculate the area of the track( b)cost of putting up a fence along the outer circle at the rate of rate 12 per metre​

Answers

Answered by payallusi66
0

Answer:

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• According to the Question Now :

\implies \tt Inner \:Circumference = 2\pi r⟹InnerCircumference=2πr

\implies \tt 176 = 2 \times \dfrac{22}{7} \times r⟹176=2×

7

22

×r

\implies \tt \cancel{176}\times \dfrac{7}{ \cancel{44}} = r⟹

176

×

44

7

=r

\implies \tt 4 \times 7 = r⟹4×7=r

\implies \blue{\tt r = 28m}⟹r=28m

\rule{300}{1}

⇒ Radius ( R ) = Radius ( r ) + Width

⇒ Radius ( R ) = 28 m + 7 m

⇒ Radius ( R ) = 35 m

\rule{300}{1}

(a) Area of the Track :

\longrightarrow \tt Area \:of \:Track = Outer \:Area - Inner \: Area⟶AreaofTrack=OuterArea−InnerArea

\longrightarrow \tt Area \:of \:Track = \pi {(R)}^{2} - \pi {(r)}^{2}⟶AreaofTrack=π(R)

2

−π(r)

2

\longrightarrow \tt Area \:of \:Track = \pi( {(R)}^{2} - {(r)}^{2} )⟶AreaofTrack=π((R)

2

−(r)

2

)

\longrightarrow \tt Area \:of \:Track = \dfrac{22}{7} ( {(35)}^{2} - {(28)}^{2} )⟶AreaofTrack=

7

22

((35)

2

−(28)

2

)

\longrightarrow \tt Area \:of \:Track = \dfrac{22}{7}(35 + 28)(35 - 28)⟶AreaofTrack=

7

22

(35+28)(35−28)

\longrightarrow \tt Area \:of \:Track = \dfrac{22}{\cancel7} \times 63 \times \cancel7⟶AreaofTrack=

7

22

×63×

7

\longrightarrow \tt Area \:of \:Track = 22 \times 63⟶AreaofTrack=22×63

\longrightarrow\large\boxed{\tt Area \:of \:Track = 1386 {m}^{2}}⟶

AreaofTrack=1386m

2

∴ Hence, Area of the Track is 1386 m².

\rule{300}{2}

(b) Cost of putting a fence along the outer circle @ Rs. 12 per Metre.

\longrightarrow \tt Cost = Circumference \times Rate⟶Cost=Circumference×Rate

\longrightarrow \tt Cost = 2\pi R \times Rate⟶Cost=2πR×Rate

\longrightarrow \tt Cost = (2 \times \dfrac{22}{ \cancel7} \times \cancel35) \times Rs. 12⟶Cost=(2×

7

22

×

3

5)×Rs.12

\longrightarrow \tt Cost = (2 \times 22\times 5)\times Rs.12⟶Cost=(2×22×5)×Rs.12

\longrightarrow\tt Cost = 220 \times Rs.12⟶Cost=220×Rs.12

\longrightarrow \large \boxed{\tt Cost = Rs. \: 2640}⟶

Cost=Rs.2640

∴ Cost of Outer Fencing is Rs. 2640.

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