the inner circumference of a circular track is 220 m.the track is 7m wide everywhere.calculate the cost of putting up a fence along the outer circle at the rate of rupee 2 per meter.plz solve this question
Answers
Answered by
309
inner circumference = 220
2 π r = 220
r *2* 22 = 220 * 7
r = 35 m [ inner radius ]
inner radius , r₁ = 35 m
outer radius , r₂ = 35 + 7 = 42 m
outer circumference = 2 π r ₂
= 2 * ( 22 / 7 ) * 42 = 264 m
Cost of fencing = Rs 2 * 264 = Rs 528
2 π r = 220
r *2* 22 = 220 * 7
r = 35 m [ inner radius ]
inner radius , r₁ = 35 m
outer radius , r₂ = 35 + 7 = 42 m
outer circumference = 2 π r ₂
= 2 * ( 22 / 7 ) * 42 = 264 m
Cost of fencing = Rs 2 * 264 = Rs 528
bd4885618:
thnx for ur help
Answered by
29
Answer:
Circumference of inner side = 220m
⇒2πr=220⇒r=
44
220×7
=35m
Now, width of track =7m
∴ Outer radius =35+7=42m
Therefore outer circumference =2πR=2×
7
22
×42=264m
∴ Cost of fencing = Rs. (264×2) = Rs. 528
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