the inner circumference of a circular track is 242m .the track is uniformly 7m wide .find the area of track
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Answer:
1848 m^2
Step-by-step explanation:
Area of the track = Outer area - inner area
circumference = 2 pi r = 242 m
2 × 22/7 × r = 242
r = (242 × 7) / 44
r (i)= 154 / 4 = 38.5 cm
outer radius = inner radius + width
= 38.5 + 7 m
r (o)= 45.5 m
Area of track = pi [r(o)]^2 - [pi r(i)]^2
= 22/7 (45.5 × 45.5) - 22/7 (38.5 × 38.5)
= 6506.5 - 4658.5
= 1848 m ^2
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