the inner circumference of a circular track is 264 and the width of the track is 7 M calculate the cost of putting a persons along the outer circle of the clock at the rate of rupees 3.50 p.m. and the area of the track
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inner radius
Circumference of inner circle 2×22/7×r=264
r=42
outer radius R=42+7 =49
area of track =22/7(R^2-r^2)
22/7(49^2-42^2)=2002
cost of putting track = 2002×3.5 =7007
Circumference of inner circle 2×22/7×r=264
r=42
outer radius R=42+7 =49
area of track =22/7(R^2-r^2)
22/7(49^2-42^2)=2002
cost of putting track = 2002×3.5 =7007
Bhavya154328:
it is wrong the cost
cost is 1078
yes
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