the inner circumference of a circular track is 330 5he track is 10.5 m wide everywhere. calculate the cost of putting up fence along the outer circle at rate of rs 20 per metre.
Answers
Answered by
58
Hey there!
Inner track's Circumference = 330 metres
2πr = 330
⇒ 2 × 22/7 × r = 330
⇒ 44/7 × r = 330
⇒ r = 330 × 7/44
⇒ r = 52.5 m
Now, Radius of outer track = 52.5 + 10.5 m = 63 metres
Outer track's Circumference = 2πr
= 2 × 22/7 × 63
= 396 m
Therefore,
The cost of putting fence around the Outer track @ Rs.20 per m:
⇒ 396 × 20 = 7920
Hence,
The answer to your question is = Rs. 7920
HOPE IT HELPED ^_^
Inner track's Circumference = 330 metres
2πr = 330
⇒ 2 × 22/7 × r = 330
⇒ 44/7 × r = 330
⇒ r = 330 × 7/44
⇒ r = 52.5 m
Now, Radius of outer track = 52.5 + 10.5 m = 63 metres
Outer track's Circumference = 2πr
= 2 × 22/7 × 63
= 396 m
Therefore,
The cost of putting fence around the Outer track @ Rs.20 per m:
⇒ 396 × 20 = 7920
Hence,
The answer to your question is = Rs. 7920
HOPE IT HELPED ^_^
Answered by
72
Heya !!!
This is your answer.
Given :-
Inner circumference of a circle = 330 m.
Circumference= 2πr = 330
2πr = 330
22/7 × r = 165
r = 165 × 7/22
r = 1155/22 = 52.5 m.
The track is 10.5 m wide. So, outer radius = 52.5 + 10.5 = 63 m.
therefore, circumference of outer circle = 2πr
= 396 m.
Cost of fencing = Rs. 20/m.
So, cost of fencing 308 m ....
= 396 × 20
= 7920
Hence, the cost of fencing is Rs. 7920.
Hope it helps ki
This is your answer.
Given :-
Inner circumference of a circle = 330 m.
Circumference= 2πr = 330
2πr = 330
22/7 × r = 165
r = 165 × 7/22
r = 1155/22 = 52.5 m.
The track is 10.5 m wide. So, outer radius = 52.5 + 10.5 = 63 m.
therefore, circumference of outer circle = 2πr
= 396 m.
Cost of fencing = Rs. 20/m.
So, cost of fencing 308 m ....
= 396 × 20
= 7920
Hence, the cost of fencing is Rs. 7920.
Hope it helps ki
RehanAhmadXLX:
Thx for Brainliest mark
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