the inner circumference of a hollow cylindrical pipe is 4.5 metre and the outer circumference is 4.6 metre find the cost of painting both its inner and Outer side @ rupees 20 per metre square if it is 8 tall
Answers
The cost of painting both its inner or outer side at the rate of 20 per square meter is Rs. 1454.
Step-by-step explanation:
The height of the cylinder is given as = 8 m
Step 1:
The inner circumference of the hollow cylinder pipe = 4.5 m
Let the inner radius of the base of the hollow cylinder be “r” m.
∴ 2πr = 4.5
⇒ r = [4.5*7] / [2*22]
⇒ r = 0.715 m
∴ Area of the inner side of the hollow cylinder to be painted is given by,
= 2πrh
= 2 * 22/7 * 0.715 * 8
= 35.95 m² …. (i)
Step 2:
The outer circumference of the hollow cylinder pipe = 4.6 m
Let the outer radius of the base of the hollow cylinder be “R” m.
∴ 2πR = 4.6
⇒ R = [4.6*7] / [2*22]
⇒ R = 0.731 m
∴ Area of the outer side of the hollow cylinder to be painted is given by,
= 2πRh
= 2 * 22/7 * 0.731 * 8
= 36.75 m² ….. (ii)
Step 3:
Now, from (i) & (ii), we get
The total area of the hollow cylinder to be painted is,
= 35.95 + 36.75
= 72.7 m²
The cost of painting per meter square is given as = Rs. 20
Thus,
The cost of painting both the inner and outer side of the hollow cylinder is,
= 72.7 m² * Rs. 20
= Rs. 1454
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A hollow cylindrical pipe has inner circumference 44dm and outer 45 dm. Find the cost of painting it from both sides at Rs2 per m², if its length is 3.5m.
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Step-by-step explanation:
Answer is Rs.1456
Hope it will be helpful for all