The inner circumference of circle is 440 and outer circumference of circle is 506 . Find the width and area of track
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The wdth of track is 506-440=66
And area = area of larger circle-area of smaller circle
=22/7*506*506–22/7*440*440
=196227.42857units
Mark this as braintiest
And area = area of larger circle-area of smaller circle
=22/7*506*506–22/7*440*440
=196227.42857units
Mark this as braintiest
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inner circumference=440
Πr²=440
22/7×r²=440
r²=140
circumference of circle=506
22/7×R²=506
R²=161
area of track=22/7(R²-r²)
=22/7(161-140)
=22×21/7
=22×3
= 66cm²
Πr²=440
22/7×r²=440
r²=140
circumference of circle=506
22/7×R²=506
R²=161
area of track=22/7(R²-r²)
=22/7(161-140)
=22×21/7
=22×3
= 66cm²
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