Question

the inner diameter of a circular well is 3.5 it is 10 metre deep find its inner curved surface area​
please help me
it's urgent
don't write useless things when I will report your answer ​

Answer 1

Answer:

inner radius= 1.75m

height= 10m

curved surface area of cylinder is 2πrh

2×22/7 ×1.75×10

110 m²

answer

hope it helped you

Answer 2

$\huge \tt {Given :-}$

• Inner diameter of a circular well = 3.5m.
• Depth of a circular well (h) = 10m.

$\huge \tt {To \: Find :-}$

• Inner curved surface area of a circular well.

$\huge \tt {Solution :-}$

First, we need to find the inner radius of a circular well.

Radius = $\sf \blue{\dfrac{Diameter \: (d)}{2} }$

Given,

• Inner diameter of a circular well (d) = 3.5m.

→ $\dfrac{3.5}{2}$

→ $\dfrac{35}{2 \times 10}$

→ $\dfrac{ \cancel{35}}{ \cancel{20}}$

→ $1.75m$

Now, we have to find the inner curved surface area of a circular well.

Inner curved surface area = $\large\blue{ 2 \pi rh}$

• r = 1.75m.
• h = 10m.

Now, put the values in the formula of Inner C.S.A. of a cubical well.

→ $2 \times \dfrac{22}{7} \times 1.75 m \times 10 m$

→ $2 \times \dfrac{22}{7} \times \dfrac{175}{10 \cancel0} \times 1 \cancel0 {m}^{2}$

→ $2 \times \dfrac{22}{ \cancel7} \times \dfrac{ \cancel{175}}{10} {m}^{2}$

→ $2 \times {22} \times \dfrac{ \cancel{25}}{ \cancel{10}} {m}^{2}$

→ $\dfrac{ \cancel2 \times 22 \times 5}{ \cancel2} {m}^{2}$

→ $\dfrac{110}{1} {m}^{2}$

→ ${110m}^{2}$

Hence, Inner curved surface area of a cubical well is $\sf {110m}^{2}$