Question

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find the cost of
plastering its inner curved surface at Rs 4 per square metre.

Answer 1

Answer:

The inner diameter of a circular well is 3.5 m. It is 10 m deep. Find

i) its inner curved surface area,

ii)the cost of plastering this curved surface at the rate of ₹ 40 per m².

Solution:

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 m

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 m

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 m

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 mi) The inner curved surface area of the well = 2πrh

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 mi) The inner curved surface area of the well = 2πrh= 2 × 22/7 × 1.75 m × 10 m

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 mi) The inner curved surface area of the well = 2πrh= 2 × 22/7 × 1.75 m × 10 m= 110 m²

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 mi) The inner curved surface area of the well = 2πrh= 2 × 22/7 × 1.75 m × 10 m= 110 m²ii) We can calculate the cost of plastering by multiplying the curved surface area of the well and the rate of plastering per square meter.

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 mi) The inner curved surface area of the well = 2πrh= 2 × 22/7 × 1.75 m × 10 m= 110 m²ii) We can calculate the cost of plastering by multiplying the curved surface area of the well and the rate of plastering per square meter.Cost of plastering the curved surface area at ₹ 40 per m2 = 110 × 40 = ₹ 4400

Since the well is cylindrical its curved surface area with base radius 'r' and height 'h' is 2πrh.Diameter of the well, d = 3.5 mRadius of the well, r = d/2 = 3.5/2 m = 1.75 mDepth of the well, h = 10 mi) The inner curved surface area of the well = 2πrh= 2 × 22/7 × 1.75 m × 10 m= 110 m²ii) We can calculate the cost of plastering by multiplying the curved surface area of the well and the rate of plastering per square meter.Cost of plastering the curved surface area at ₹ 40 per m2 = 110 × 40 = ₹ 4400Thus, the inner curved surface area is 110 m² and the cost of plastering the circular well is ₹ 4400.

Step-by-step explanation:

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