The inner diameter of a circular well is 3.5 m it is 10m deep (1)find inner curved surface area (2) find the cost of plastering this curved surface the at rate of rupes 40 per meter
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Answered by
21
Given,
diameter = 3.5 m. Radius = 3.5/2 = 35/20 = 7/4m
height = 10m
CSA of cylinder = 2πrh
= 2*22/7*7/4*10
44/4*10= 110m²
Therefore CSA = 110m².
ii)
Cost of plastering = CSA * RATE OF PLASTERING
= 110*40
4400 Rupees
Hope it helps.
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diameter = 3.5 m. Radius = 3.5/2 = 35/20 = 7/4m
height = 10m
CSA of cylinder = 2πrh
= 2*22/7*7/4*10
44/4*10= 110m²
Therefore CSA = 110m².
ii)
Cost of plastering = CSA * RATE OF PLASTERING
= 110*40
4400 Rupees
Hope it helps.
Please mark my answer brainliest!
Answered by
3
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