The inner diameter of a circular well is 3.5m. It is 10m deep. Find
i)its inner curved surface area
ii)The cost of plastering this curved surface at the rate of Rs40 per m².
Answers
Answered by
544
(1)inner curve surface area =2πrh
where r is inner radius
h is height of well
now,
surface area=2 x 22/7 x 7/4 x 10
=110 m^2
(2) the cost of plastering in this curve surface=area of curve surface x rate
=110 x 40= 4400 Rs
where r is inner radius
h is height of well
now,
surface area=2 x 22/7 x 7/4 x 10
=110 m^2
(2) the cost of plastering in this curve surface=area of curve surface x rate
=110 x 40= 4400 Rs
ameer487:
wat
yes i correct it
r=3.5/2
please again check
i wrote the formula was 2pirh+2pirxr
dear this is wrong
sir only ask curve surface area
no total area
i thought tsa
okay please correct it
Answered by
85
Inner csa= 110 sqrmts, cost of plastering=110x40=4400sqrmts
Attachments:
Ameer , csa = 2*pi*r*h but u find tsa
sorry
i thought tsa
it's ok
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