Question

the inner diameter of a circular well is 3.5m. It is 10m deep. Find it inner curved surface area. the cost of plastering this curved surface at rate of rupees 40 per m²​

Answer 1

Answer:

(i)2r = 3.5 m

=> r = 3.5/2

=>  r= 1.75 m

h= 10 m  (given)

Inner curved surface area = 2πrh

=2 x 22/7 x 1.75 x 10 = 110m^2

(ii) cost of plastering = 110 x 40

= rs.4400

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