the inner diameter of a circular well is 3.5m. it is 10m deep.find (i)its inner curved surface area (ii)the cost of plastering this curved surface at the rate of rs40 per m2
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Inner CSA=2×pi×3.5/2×10
=22/7×35
=22×5
=110m^2
•Since,CSA=110m^2
Cost of plastering = Inner CSA×40=110×40
=Rs.4400
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=22/7×35
=22×5
=110m^2
•Since,CSA=110m^2
Cost of plastering = Inner CSA×40=110×40
=Rs.4400
Pls.mark thanks and Brainliest
Aditya2321:
Thank you Warrior 10 or Saurabh
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