Question

The inner diameter of a circular well is 7 meter and  it is 10 meter deep. Its inner curved surface area is​(trisha)​

Answer 1

Given:-

• Inner diameter is 7 m, So, Radius= 7/2 = 3.5 m (r)
• Height= 10m (h)

To Find:-

• Inner curved surface area (CSA)

Formula used:-

$\sf \large { \boxed{ \red{ \sf{CSA \tiny(Cylinder) \large{ = 2\pi rh}}}}}$

Putting values,

$\sf \large { \boxed{ \sf \implies{CSA \tiny(Cylinder) \large{ = 2 \times \frac{22}{7} \times 3.5 \times 10}}}}$

$\sf \large { \boxed{ \sf \implies{CSA \tiny(Cylinder) \large{ = 2 \times \frac{22}{7} \times \frac{35}{ \cancel{10}} \times \cancel{10}}}}}$

$\sf \large { \boxed{ \sf \implies{CSA \tiny(Cylinder) \large{ = 2 \times \frac{22}{ \cancel7} \times \cancel7 \times 5}}}}$

$\sf \large { \boxed{ \sf \implies{CSA \tiny(Cylinder) \large{ = 44 \times5 }}}}$

$\sf \large { \boxed{ \sf \implies{ \blue{{CSA \tiny(Cylinder) \large{ = 220 {m}^{2} }}}}}}$

__________________________

So, Required curved surface area of cylinder= 220 m²