The inner diameter of a circular well is 7 meter and it is 10 meter deep. Its inner curved surface area is(trisha)
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given, diameter= 7m
then, radius= 3.5m and height= 10m
we know that, curved surface area of a cylinder= 2πrh so,
=> 2*3.14*(3.5*10)m
=> 6.28*35m²
=219.8m²
therefore, inner curved surface area of the circular well= 219.8m²
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Answered by
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Answer:
Inner diameter of a well
=
3.5
m
∴
Inner Radius
(
r
)
=
3.5
2
=
1.75
m
and, depth (or) height,
(
h
)
=
10
m
(
i
)
∴
Inner curved surface area of the well
=
2
π
r
h
=
2
×
22
7
×
1.75
×
10
=
440
×
0.25
=
110
m
2
(
i
i
)
Rate of plastering per
m
2
=
R
s
.
40
∴
Total cost of plastering inner curved surface area
=
R
s
.
40
×
110
=
R
s
.
4400
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