Question

The inner diameter of a cylindrical vessel is 3.5m.It is 100m deep.Find the cost of polishing the inner curved surface area at the rate of rupees 4 per m^2.
pls tell fast​

Answer 1

Answer:

total cost=Rs.4400

Step-by-step explanation:

curved surface area=2πrh

            diameter=3.5 so radius=1.75,h=100

                         area=2*π*1.75*100

                                =2*π*175

                                =350*π=1100m²

total cost=1100*4=Rs.4400

Answer 2

GIVEN :

• Inner diameter of a cylindrical vessel = 3.5 m.
• Height of a cylindrical vessel= 100 m.

TO FIND :

• The cost of polishing the inner curved surface area (CSA) at the rate of ₹ 4 per m².

SOLUTION :

To find the cost = ?

The inner diameter of a cylindrical vessel = 3.5 m.

So radius = $\sf \dfrac {3.5}{2} \ = \ 1.75 \ m$

Inner curved surface area (CSA) = $\sf 2 \pi rh$

Put the values given values.

$\implies \sf 2 \times \dfrac {22}{7} \times 1.75 \times 1.75 \times 100$

$\implies \sf 1925 m^{2}$

Total cost of polishing = 1925 × 4

$\therefore$ Total cost of polishing is ₹ 7700.