Question

the inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 CM the length of the pipe is 35 cm find the mass of the pipe is 1 cm cube of what has mass of 0.6 grams

Answer 1

Heya Frnd ..........☺

Inner radius (r) = 24/2 = 12 cm

Outer radius ( R ) = 28/2 = 14 cm

height = 35 cm


Now,

Volume of the pipe = πh (R² - r²)

$= \: \frac{22}{7} \times 35 \times ( {14}^{2} - {12}^{2} )$
$= > \: 110 \: (196 \: - \: 144)$

$= > \: 110 \: \times \: 52$

$= > \: 5720 \: {cm}^{3} ..........( \: 1 \: )$

____________________

NOW,

mass of 1 cm ³ = 0.6 gm

THEREFORE,

mass of 5720 cm³

=> 5720 × 0.6

= > 3432 gms ................★ ANS ★

______☺☺☺______

HOPE IT WILL HELP U.............✔

Answer 2

inner radius of pipe= 12cm
length of pipe = 35 cm
volume of pipe= 22/7×12 ×12 ×35
= 15840 × 0.6
= 9504 g