the inner diameter of a cylindrical wooden pipe is 24 cm and it outer diameter is 28 CM the length of the pipe is 35 cm find the mass of the pipe if one centimetre square of wood mass of 0.6 gram
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Answer:
3.432 kg
Step-by-step explanation:
Find the radius:
r1 = 28 ÷ 2 = 14 cm
r2 = 24 ÷ 2 = 12 cm
Find the volume of the wood:
Volume = πh(r1² - r2²)
Volume = π(35)(14² - 12²)
Volume = 5720 cm³
Find the mass of the pipe:
1 cm³ = 0.6g
5720 cm³ = 0.6 x 5720 = 3432g or 3.432 kg
Answer: The mass is 3.432kg
PLEASE MARK IT BRAINLIEST AND FOLLOW ME.
3.432 kg
Step-by-step explanation:
Find the radius:
r1 = 28 ÷ 2 = 14 cm
r2 = 24 ÷ 2 = 12 cm
Find the volume of the wood:
Volume = πh(r1² - r2²)
Volume = π(35)(14² - 12²)
Volume = 5720 cm³
Find the mass of the pipe:
1 cm³ = 0.6g
5720 cm³ = 0.6 x 5720 = 3432g or 3.432 kg
Answer: The mass is 3.432kg
PLEASE MARK IT BRAINLIEST AND FOLLOW ME.
der20:
thanks
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