Question

The inner diameter of a cylindrical wooden pipe is 24cm and it's outer diameter bis 28cm. The length of the pipe is 35cm find the mass of the pipe if 1cm3 of wood has a mass of 0.6g?

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Answer 1

hey...

Answer:- 3.432 kg

find the radius:-

r1=28÷2=14

r2=24÷2=12

find volume:-

volume=πh(r1^2-r2^2)

volume=5720cm^3

find the mass of the pipe:-

1 cm^3=0.6 g

5720 cm^2=0.6×5720

=3432g or 3.432 kg

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#BE BRAINLY#

Answer 2

Find the radius:

r1 = 28 ÷ 2 = 14 cm

r2 = 24 ÷ 2 = 12 cm

Find the volume of the wood:

Volume =  πh(r1² - r2²)

Volume =  π(35)(14² - 12²)

Volume = 5720 cm³

Find the mass of the pipe:

1 cm³ = 0.6g

5720 cm³ = 0.6 x 5720 = 3432g or 3.432 kg