The inner diameter of a cylindrical wooden pipe is 28 cm and its outer
diameter is 32 cm. The length of the pipe is 70 cm. Find the mass of
the pipe, if 1 cm³ of wood has a mass of 1.5 g.
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Step-by-step explanation:
Here,
inner radius (r) = 24/ 2 cm = 12 cm
Outer radius (R) = 28/ 2 cm = 14 cm
, h = 35 cm
Volume of the wood used in the pipe = π(R2 – r2) h
= 22/ 7 [(14)4 – (12)2] × 35 cm3
= 22/ 7 × 26 × 2 × 35 cm3
= 5720 cm3
Mass of 1 cm3 of wood
= 0.6 g
∴ Mass of 5720 cm3 of wood
= 0.6 × 5720 g
= 3432 g.
Hope it helps ☺☺
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