The inner diameter of a metal cylindrical pipe is 38 cm and its outer diameter is 45 cm. If its height is 1 m then find the mass of the pipe if 1cm³ weighs 5 g
Answers
Height of cylindrical pipe (h) = 1 m
= 100 cm
Inner diameter (d) = 38 cm
Inner radius (r) = 19 cm
Outer diameter (D) = 45 cm
Outer radius (R) = 45/2 cm
volume of cylindrical pipe = π h (R² - r²)
= 22 × 100 [ ( 45/2 )² - ( 19 )² ]
7
= 22 × 100 [ 2025/4 - 361 ]
7
= 22 × 100 × 581
7 × 4
= 22 × 25 × 83
= 45650 cm³
mass of 1 cm³ = 5 g
mass of 45650 cm³ = 5 × 45650
= 228250 grams
= 228.250 kg
Answer:
Height = 1m = 100cm
Inner diameter = 38 cm
inner radius = 19 cm
Inner volume = πr²h
vol = 361πh
Outer diameter = 45 cm
Outer radius = 45/2 cm
outer volume = πr²h
vol = 506.25πh
Net volume = outer vol – inner vol
506.25πh – 361πh
πh ( 506.25 – 361 )
145.25πh
145.25 x 22/7 x 100 = 45650 cm³
Net volume = 45650 cm³
1 cm³ = 5g
45650 cm³ = 45650 x 5 = 228250 g
Weight of pipe = 228.250 kg
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