the inner diameter of cylindrical wooden pipe is 24 cm and outer diameter = 28cm the length of pipe is 35cm find the mass of pipe if 1cm3 of wood has a masa of 0.6 g
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Here Inner radius (r) = 24/2 = 12cm
Outer radius (R) = 28/2 = 14 cm
h = length of pipe = 35 cm
Volume of the pipe =
= πR2h - πr2h
= πh ( R2 - r2 )
= 22/7 × 35 × (142 - 122 )
= 22/7 ×35 × (14 - 12) (14 + 12)
= 22/7 × 35 × 2 × 26
= 5720cm 3
Now, 1 cm3 wood = 0.6g
5720cm3 = (5720 × 0.6)g
= 3432.0 g
= 3.432 kg
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