the inner diameter of the cylindrical wooden pipe is 24 cm and its outer diameter is 28 CM the length of wooden pipe is 35 cm find the total surface area of the pipe
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Inner diameter = 24cm
Inner radius (r) = 12cm
Outer diameter = 28cm
Outer radius (R) = 14cm
Length= 35cm (=height)
(Total surface area includes the inner surface, outer surface as well as the area of two rings.)
Total surface area= 2πrh+2πRh+2πR^2+2πr^2
= 2π(rh+Rh+R^2+r^2)
= 2*22/7(12*35+14*35+14^2+12^2)
=2*22/7(420+490+196+144)
= 2*22/7(1250)
= (44*7)(1250)
= 7857. 14 cm^2 !!!ANSWER!!!
Inner radius (r) = 12cm
Outer diameter = 28cm
Outer radius (R) = 14cm
Length= 35cm (=height)
(Total surface area includes the inner surface, outer surface as well as the area of two rings.)
Total surface area= 2πrh+2πRh+2πR^2+2πr^2
= 2π(rh+Rh+R^2+r^2)
= 2*22/7(12*35+14*35+14^2+12^2)
=2*22/7(420+490+196+144)
= 2*22/7(1250)
= (44*7)(1250)
= 7857. 14 cm^2 !!!ANSWER!!!
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