Math, asked by vishal19992, 1 year ago

The inner radius and height of an open cylindrical vessel are 2.1/3 cm and 9cm respectively.what is the greatest number of cubic cm of liquid it can hold?

Answers

Answered by navin747589
0

Answer:

Use the formula πr^2h

Here it will be 22/7*2.1/3*2.1/3*9

it will give = 13.86 cubic cm

Answered by nitkumkumar
0

Answer:

The greatest number of cm³ of liquid cylindrical vessel can hold = 154  cm³

Step-by-step explanation:

Here, the inner radius of open cylindrical vessel,r = 2(1/3) cm  (It is given in mixed fraction)

                                                                            =  7/3 cm

Also, the height of open cylindrical vessel , h =  9  cm

The value of  π  =  22/7

As,  the greatest number of cubic cm of liquid cylindrical vessel can hold = volume of cylindrical vessel

=>  the greatest number of cm³ of liquid cylindrical vessel can hold = πr²h

                               =  (22/7) * (7/3) * (7/3) * 9

                               =  154  cm³

Thus, the greatest number of cm³ of liquid cylindrical vessel can hold = volume of open cylindrical vessel =  154  cm³

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