Question

The inner radius of a metallic cylindrical pipe is 8cm and its outer radius is 9cm. If the
length of the pipe is 14 cm, find its volume.​

Answer 1

Given:-

• Inner radius of a metallic cylindrical pipe is 8cm.
• Outer radius of a metallic cylindrical pipe is 9cm.
• Length of pipe is 14cm

To find:-

• Volume of cylindrical pipe.

Solution:-

• Let's inner radius be (r) cm
• Let's outer radius be (R) cm

Volume of cylinder :- πr²h

:$\implies \sf{ \bigg( \pi \times \ R^2 \times h \bigg) - \bigg( \pi \times r^2 \times h \bigg)}$

:$\implies \sf{ \pi \times h( R^2 - r^2)}$

:$\implies \sf{ \dfrac{22}{ \cancel{7}} \times \cancel{14} \times (81 - 64)}$

:$\implies \sf{ 22 \times 2 \times 17}$

:$\implies \; \large\bold{\underline{\underline{\boxed{\sf{\red{\dag \; 748cm^3}}}}}}$

$\rule{200}{2}$

Answer 2

$\huge\purple{\underline{\underline{\pink{Ans}\red{wer:-}}}}$

$\sf{The \ volume \ of \ metallic \ pipe \ is}$

$\sf{748 \ cm^{3}}$

$\sf\orange{Given:}$

$\sf{For \ metallic \ cylindrical \ pipe,}$

$\sf{\implies{Inner \ radius \ (r1)=8 \ cm}}$

$\sf{\implies{Outer \ radius \ (r2)=9 \ cm}}$

$\sf{\implies{Height \ (h)=14 \ cm}}$

$\sf\pink{To \ find:}$

$\sf{The \ volume \ of \ a \ metallic \ cylindrical}$

$\sf{pipe.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Volume \ of \ cylinder=\pi\times \ r^{2}\times \ h}$

$\sf{…formula}$

$\sf{\therefore{Volume \ of \ metallic \ pipe}}$

$\sf{\implies{(\pi\times \ r2^{2}\times \ h)-(\pi\times \ r1^{2}\times \ h)}}$

$\sf{\implies{\pi\times \ h(r2^{2}-r1^{2})}}$

$\sf{\implies{\frac{22}{7}\times14\times(9+8)(9-8)}}$

$\sf{\implies{22\times2\times17}}$

$\sf{\implies{748 \ cm^{3}}}$

$\sf\purple{\tt{\therefore{The \ volume \ of \ metallic \ pipe \ is}}}$

$\sf\purple{\tt{748 \ cm^{3}}}$