Question

The inner radius of a well is 3.5 m .It is 20 m
deep Find its inner curved surface area :​

Answer 1

The inner radius of a circular well =

$\binom{3.5}{2} m$

= 1.75 m

DEPTH OF CIRCULAR WELL = 10 m

INNER CURVED SURFACE OF THE WELL =

$2\pi \: r \: h$

=

$(2 \times \frac{22}{7} \times 1.75 \times 10) {m}^{2}$

$(2 \times \frac{22}{7} \times \frac{175}{100} \times 10) {m}^{2}$

$(2 \times 22 \times \frac{25}{10}) {m}^{2}$

$= 110 {m}^{2}$