Math, asked by veerpal076kaur, 11 months ago

The inner radius of pipe is 8cm and length 21cm. How much water can 12m of this pipe hold??

Answers

Answered by cmshebeeb
1

Step-by-step explanation:

volueme of pipe =πr^2 h

here r=8cm and h=12m

then V= π×8×8×1200

V= 241274 cm ^3

Answered by chai06vijay
2

Answer:

Step-by-step explanation:

radius = 8 cm = 0.08 m

length = 21 cm = 0.21 m

Volume = \pi r^{2} h

= \frac{22}{7}*0.08*0.08*0.21\\=22*0.0064*0.3\\

1 m of the pipe can hold

= 22*1*1*0.3

= 0.66m^{3}

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