the inner surface of a hemispeherical dome of a building needs to be painted.if the circumference of the base of the dome is 17.6m find the cost of painting it given the cost of painting is rs 5 per 100cm^2
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thanks for explanation
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Since only the rounded surface of the dome is to be painted we need to find the curved surface area of the hemisphere to know the extent of painting that needs to be done.
Now, circumference of base of the dome = 17.6 m Therefore 17.6 = 2πr
So, The radius of the dome =17.6×
2×22
7
m
= 2.8 m
The curved surface area of the dome =2πr
2
=2×
7
22
×2.8×2.8m
2
=49.28m
2
Now, cost of painting 100 cm
2
is Rs. 5
So, cost of painting 1 m
2
= Rs. 500
Therefore, cost of painting the whole dome
=Rs.500×49.28
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