CBSE BOARD XII, asked by crazy01, 8 months ago

The input control parameter of a JFET is ..............? (A) GATE VOLTAGE (B) Source voltage (C) Drain voltage

Answers

Answered by gyaneshwarsingh882
0

Answer:

IDSS = Maximum saturation current

VGS = Gate to source voltage

VP = Pinched-off voltage

 

Calculation:

Given:

Vp = -4 V

ID = 2 mA = 2 × 10-3 A

Gate voltage (VGS) = -2 V

 

 

Answered by ravilaccs
0

Answer:

The correct answer is Option A

Explanation:

IDSS = Maximum saturation current

VGS = Gate to source voltage

VP = Pinched-off voltage

Given:

Vp = -4 V

ID = 2 mA = 2 * 10^-3 A

Gate voltage (VGS) = -2 V

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