Question

The input power in a two-hole directional coupler is 1mW. The coupler has a coupling co-efficient of

X dB and directivity of 50 dB. Calculate the power in all ports
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Answer 1

Answer:

Explanation:

An Isolator has insertion loss of 0.5 dB, an isolation of 25 dB and VSWR of 2,find the S-matrix.Sol. Insertion loss = 0.5 dB = -20 logIS21I IS21I = 10-(0.5/20)= 10- 0.025Isolation = 25 dB = -20 logIS12I IS12I = 10-(25/20)= 10- 1.2 Since VSWR = 1.5, so reflection coefficient = (S-1)/(S+1) = 0.2S11= S22= 0.2Therefore S-matrix of an Isolator

It is a four-port device commonly used for coupling a known fraction of the microwave power to a port (coupling port) in the auxiliary line while flowing from the input port to the output port in the mainline. The remaining is an isolated port and matched terminated. Construction:- directional coupler has four ports, primary waveguide 1-2 and secondary waveguide 4-3. Port 1 and port 4 are isolated Port 2 and port 3 are isolated If the signal is incident in port 1, it is distributed in between port 2 and port 3, but not on port 4 due to perfect isolation. Characteristics of directional Coupler:- 1. Coupling and Coupling Factor:- C = 10 log(P1/P3) , dB2. Transmission loss or Insertion loss :- T = 10 log(P1/P3) 3. Directivity:- D = 10 log (P3/P4), 4. Return Loss:- R = 10 log (Pi/Pr), 5. Isolation:- I = 10 log(P1/P4), 6. Directivity D = Isolation - C Nu. The input power in a two-hole directional coupler is 1 mW. The Coupler has a coupling factor of 15 dB and directivity of 30 dB. Calculate the power in all

, dB

dB

dB

dB