The input power to an electric motor is 200kw.
its efficiency is 80%. it operates a crane of efficiency
90%
if the crane u lifting a dead d 3.6tonns
the velocity with which the load moves is
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Power with which crane lifts the load =0.8×0.9 × input power
P=0.8×0.9×200 kW
Now, P=
F
.
v
Here, F=mg (since there is no acceleration)
10
3
×0.8×0.9×200=3.6×10
3
×10×v
⇒v=4 m/s
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