The input powers of a motor are 300 W in 20sec it lifts a load of 40 N through a height of 60m. What is the efficiency of the motor
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Output power is work done per unit time = mgh/t
= 200 kg × 9.8 m/s² × 4 m/s
= 7840 W
Efficiency of motor = [(Output power) / (Input power)] × 100
70 = [7840 / (Input power)] × 100
Input power = 7840 × 100/70 = 11.2 kW
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