Question

The inside circumference of a circular field is 1188 m. A road 7 m wide is constructed on the outside around it.
Find its area.
(1) 8070 m2
(2) 8270 m2
(3) 8370 m2
(4) 8470 m2​

Answer 1

Step-by-step explanation:

Circumference of circular field

$2\pi \times r$

We are given that The inner circumference of a circular field is 1188m.

$= > 2\pi \times r = 1188m \\ 2 \times \frac{22}{7} \times r = 1188 \\ r = \frac{1188 \times 7}{2 \times 22} \\ r= 189m$

A road 7m wide is construct on the outside

Outer radius,R=189+7=196m

Area of Path=Outer Area-Inner Area

$\frac{22}{7} \times (196 {}^{2} - 189 {}^{2} ) \\ \frac{22}{7} \times 2695 \\ = 22 \times 7 \\ 8470m {}^{2}$

Hence the area of road is 8470 m.sq.

Answer 2

Answer:

Step-by-step explanation:

Step-by-step explanation:

Circumference of circular field

We are given that The inner circumference of a circular field is 1188m.

A road 7m wide is construct on the outside

Outer radius,R=189+7=196m

Area of Path=Outer Area-Inner Area

Hence the area of road is 8470 m.sq.