Question

The instantaneous angular position of a point on a rotating
wheel is given by the equation ϴ(t) = 2t³ – 6t². The torque
on the wheel becomes zero at
(a) t = 1s (b) t = 0.5 s
(c) t = 0.25 s (d) t = 2s

Answer 1

dt=2(3t^2)-6(2t)=>12t-12=>t=1sec