Question

The integer 2019 can be formed by placing two consecutive two-digit positive integers,
19 and 20, in decreasing order. What is the sum of all four-digit positive integers
greater than 2019 that can be formed in this way?
(A) 476 681
(B) 476861
(C) 478 661
(D) 468 671
(E) 468 761

Answer 1

Answer:

bro shaayad c hai

Step-by-step explanation:

agar sahi hai to please make me brainliest

muje bohot jarurat hai

please bro

Answer 2

Step-by-step explanation:

The next number after 2019 that follows this rule is 2120

2120, 2221, 2322, 2423, 2524, 2625 all the way to 9897, 9998

Average sum: 9998+2120/2 = 6059

But they are not in order, each is 101 apart.

So, 9998-2120 = 7878

7878/101 =78

But add the 2021 (worth one)

78 + 1 = 79

So, getting back to our 6059 x 79 numbers = 478661