Math, asked by padmaavathypa, 1 month ago

THE INTEGER N IS THE LARGEST MULTIPLE OF 15 SUCH THAT EVERY DIGIT IS EITHER 2 or 5 . THEN THE SUM OF THE DIGITS IS

Answers

Answered by vishal10012005
1

As 15 is factors as 3×5

Which means the multiple of 15 is also a multiple of 3 and 5.

As we all know that the multiple can be infinitely long.

So, minimum multiple of 15 having only digits 2 and 5 is 225.

As the number is also a multiple of 3 the sum of the digits will be a multiple of 3

So, therefore we can conclude that the sum of the digits of the multiple of 15 will be in the form of 3n

Where n is greater than 3 as we know that the smallest no. which have the mentioned properties is 225 and the digit sum of the no. is 9

If we change it to our formula we get the minimum value of n

The maximum value of n cannot be calculated as every integer greater than 3 can be the value of n.

The following given set is the solution for n

Set:- {3,4,5,6,7,8,9....}

Hope this will help U☺️

Pls. mark me as brainliest

this took me soo long to write

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