the integral of 2x raise to power
3 - 5 over x squared DX from 3 to 6
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Answer:
2x
12
+5x
9
dx
∫
x
15
(1+x
−2
+x
−5
)
3
2x
12
+5x
9
dx
∫
(1+x
−2
+x
−5
)3
2x
−3
+5x
−6
dx
1+x
−2
+x
−5
=t
−2x
−3
−5x
−6
dx=dt
−∫
t
3
dt
⇒−
−3+1
−t
3+1
+c
⇒
2t
2
1
+c⇒
2(1+x
−2
+x
−5
)
2
1
+c
⇒
2(1+x
3
+x
5
)
2
x
10
+c
Step-by-step explanation:
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