Question

The integral of ∫ex(sinx-cosx)dx is

​

Answer 1

Step-by-step explanation:

∫e

x

(sinx+cosx)dx

=∫e

x

sinx dx+∫e

x

cosx dx

=e

x

(sinx)−∫(cosx).e

x

dx+∫e

x

cosx dx

=e

x

(sinx)+c [ Where c is integrating constant]

Hope it helps

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