Question

The integral $\int\limits^\frac{1}{2}_0 \frac{In(1+2x)}{1+4x^{2}} dx$, equals:
(a) $\frac{\pi}{4}In2$
(b) $\frac{\pi}{8}In2$
(c) $\frac{\pi}{16}In2$
(d) $\frac{\pi}{32}In2$

Answer 1

I think

B)

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