Question

The integral value of a for which ax^2+ ax + a = 2x^2 - 3x - 6 has equal roots is

Answer 1

Step-by-step explanation:

For integral roots:

D=(2(a+1))

2

−4a(a+2)

D=4a

2

+8a+4−4a

2

−8a

D=4

x=

2(a+2)

−2(a+1)±2

x=

a+2

−a

=−1+

a+2

2

For

a+2

2

to be an integer, the possible values of a are 0,−1,−3 and −4

Hence, there are 4 integral values of a