Question

The integral value of a for which ax^2+ ax + a = 2x^2 - 3x - 6 has equal roots is

Answer 1

Let's solve for a.

${ax}^{2} + ax + a = {2x}^{2} - 3x - 6$

Step 1: Factor out variable a.

$a( {x}^{2} + x + 1) = {2x}^{2} - 3x - 6$

Step 2: Divide both sides by x^2+x+1.

$\large \: \frac{a( {x}^{2} + x + 1) }{ {x}^{2} + x + 1 } = \frac{ {2x}^{2} - 3x - 6}{ {x}^{2} + x + 1}$