Question

The intensity of direct sunlight befor it passes through the earth's atmosphere is 1.4kW|m^2. If it is completely absorbed, find the corresponding radiation pressure.

Answer 1

Thus the corresponding radiation pressure is P(rod) = 4.66 × 10^−6 m^−2

Explanation:

Given data:

Intensity of sunlight =  1.4 KW|m^2

Solution:

For completely absorbing surface,

P(rod) = I / c

P(rod) = 1.4 × 10^3 3.0×10^8

P(rod) = 4.66 × 10^−6 m^−2

Thus the corresponding radiation pressure is P(rod) = 4.66 × 10^−6 m^−2