Question

The intensity of electric field at a distance of 0.2m from a charge of 5mc

Answer 1

Given - Distance - 0.2m

Charge - 5mC which can be written as 5*10^-6 C

Find - Intensity of electric field.

Solution - Intensity of electric field is calculated by the formula -

E = (1/4π€)*Q/r²

In the equation, E represents electric field, 1/4π€ on solving gives the value 9*10^9. Q is charge and r is distance.

Keeping the values in equation-

E = (9*10^9)*5*10^-6/0.2²

E = 1125000 N/C

Hence, intensity of elctric field is - 1125000 N/C