Question

the intensity of electric field at any point on the surface of a charged conductor is​

Answer 1

Answer:

Zero

Explanation:

The intensity of electric field at any point on the surface of a charged conductor is zero.

This is because of the  electrostatic property of an electric conductor.

When a conductor is placed in an external electric field, there will be some movement of charges inside the conductor and they rearrange such that electric field becomes equal and opposite to external field which makes the net electric field zero

Answer 2

The intensity of electric field at any point on the surface of a charged conductor is $\bold{\frac{Q}{4 \pi \epsilon_{0} \epsilon_{r} d^{2}}}$

Explanation:

When a conductor conducts electricity, it produces electric field due to electric flux passing though it.

The electric field inside the conductor remains zero as the charge only flows through the surface of the conductor.

The electric field intensity is force excreted by one charge on another charge. It measures of the strength of electrical force per unit charge. It is given by Columb's law.

$\bold{E=\frac{Q}{4 \pi \epsilon_{0} \epsilon_{r} d^{2}}}$

The unit of electric field intensity is Newton/Columb.