Physics, asked by katherinpriyadarshin, 6 days ago

The intensity of magnetic induction at the centre of a current-carrying circular coil is B, and at a point on its axis at a dis
tance equal to its radius from the centre is B,,thenB,/B, is .​

Answers

Answered by llAssassinHunterll
0

Answer:

B

1

=

2a

μ

0

i

B

2

=

2(a

2

+a

2

)

3/2

μ

0

⋅i⋅a

2

=

2×2

2

×a

3

μ

0

ia

2

=

4

2

×a

μ

0

i

B

2

B

1

=2

2

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